Roulette Haller

7/24/2022

Roulette Haller Average ratng: 7,6/10 6993 votes

Background information
Birth name	Hannelore Haller
Born	January 14, 1950 Rendsburg, West Germany
Died	November 15, 2005 (aged 55) Tegernsee, Germany
Associated acts	Wind, Bernd Meinunger
Website	hannehaller.de

Hanne Haller (January 14, 1950 in Rendsburg, Germany - November 15, 2005 in Tegernsee, Germany; full name Hannelore Haller) was a German pop singer (genre known as 'schlager' in German), composer, writer, producer, and sound engineer.

Note: this entry is based on a translation of the entry in the German version of Wikipedia.

Life[edit]

Hanne Haller grew up in the province of Schleswig-Holstein. Her mother was an opera singer, her father a banker. While in school she played drums for 'The Rooks' in the town of Ronnenberg near Hannover. After completing school in 1968, she went on to study athletics, but had to give that up due to a serious illness. In the same year she founded a gospel choir. Later in the 60s, she performed a single consisting of two songs by Siegfried Fietz ('Wir sind nur eine Minderheit'/'We are only one minority' and 'Broadway') for the Christian publishing house 'Frohe Botschaft' ('Good News') in Wetzlar.

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She went on to study to become a medical assistant and passed the 'MTA' exam in 1970. She then worked in the X-ray and biochemistry lab of the Georg-August University/Göttingen University. In 1971 she began her musical career in earnest. She and producer Georg Moslener made the single 'Spring in Vietnam' ('Frühling in Vietnam'), which did not get much of a push. Haller learned to play the piano, and in 1971 came out with her first album 'Applause for Hanne Haller' ('Applaus für Hanne Haller'). Unfortunately, the company went bankrupt and the album was never released.

Haller then went to Munich and learned the art of being a sound engineer. She worked in many areas of the business. By the end of the 1970s she began to compose music. She started under the pseudonym 'Hansi Echer'. In 1978 singer Karel Gott performed her song 'Where the Wind Blows the Leaves' ('Wohin der Wind die Blätter weht'). Before that she had already composed the song '60 Years and Not a Bit More' ('60 Jahre und kein bisschen weise') for the actor/singer Curd Jürgens to along with his biography. After a few more singles, in 1979 she had the chance to sing before a wider audience. She took the song 'Goodbye, Chérie' to the German qualification of the Eurovision Song Contest and managed a seventh-place finish. After that she made more recordings, mostly with Bernd Meinunger writing the lyrics. Their song 'Samstag Abend' made it to number 11 on the German musical charts. In 1982 she and Meinunger founded their own musical publishing house. Haller produced songs in her own recording studio. That year, she won her first of many 'Golden Tuning Forks' ('Goldene Stimmgabel', the German version of the Grammy awards).

In 1985, Haller founded the band Wind. She didn't perform for the group herself, but she composed what has become the group's signature song, 'For All' ('Für alle'). The same year, the song earned Wind a second-place finish in the Eurovision Song Contest. After this success, she wrote songs for Daliah Lavi, Elke Martens, Katja Ebstein, Rex Gildo, Lena Valaitis, Caterina Valente, Jürgen Drews, Ingrid Peters, Wolfgang Fierek, and Milva. She also discovered Rosanna Rocci.

She continued to write, produce and perform throughout the 80s and 90s despite battling breast cancer since the mid-90s. She died on November 15, 2005. After her death, her record company announced that a previously-planned album of religious music ('Wir sind nur Gast auf dieser Welt'/'We Are Only Guests of This World') would be released.

In 2008, it surfaced that she had been in a relationship with radio and TV hostess Ramona Leiss for four years beginning in the late 1980s.^[1]^[2]

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Awards[edit]

German Record Prize, 1983
Golden Tuning Fork ('Goldene Stimmgabel') 1989, 1992 und 1997
Golden Note ('Goldene Note'), 1990
Golden Record ('Goldene Schallplatte') for 'My Dear Husband' ('Mein lieber Mann'), 1990

Best-known works[edit]

Deckel auf Deckel zu (Cover open, cover shut) 1979
Goodbye, Chérie 1979
Ich warte hier unten (I'll wait down here) 1980
Samstagabend (Saturday night)1980
Geh nicht (Don't Go) 1981
Weil du ein zärtlicher Mann bist (Because you're an endearing man) 1981
Engel fallen nicht vom Himmel (Angels don't fall from the sky) 1983
Der Sandmann (The Sandman)1985
Zeit für ein bisschen Zärtlichkeit (Time for a little tenderness) 1985
Ich hab' Dich unheimlich lieb (I love you unearthly) 1985
Starke Frauen weinen heimlich (Strong women cry secretly) 1986
Eine Wahnsinns Love Story (A hell of a Love Story) 1987
Hallo, lieber Gott (Hello, Good God) 1987
Mein lieber Mann (My dear husband) 1989
Bratkartoffeln mit Spiegelei (Fried potatoes with fried egg) 1990
Willkommen im Leben (Welcome to life) 1991
Schatz, ich will ja nicht meckern (Honey, I don't want to gripe)1992
Vater unser (Our Father) 2003
Und hättest du die Liebe nicht (And if you didn't had love) (2004)

Discography[edit]

1976 Komm, lass uns miteinander reden (Come on, let's talk)
1980 Na und (So what)
1981 Stärker als ich (Stronger than me)
1982 Augenblicke (Moments)
1984 Eines Tages (One fine day)
1985 Gefühlsroulette (Roulette of feelings)
1986 Ganz normale Frau'n (Just ordinary women)
1987 Love Story (Best Of)
1988 Liebe u.s.w. (Love etc.)
1989 Mein lieber Mann (My dear darling)
1990 Bratkartoffeln mit Spiegelei (Fried potatoes with fried egg)
1991 Willkommen im Leben (Welcome to life)
1992 Überall ist Bethlehem (Weihnachtsalbum) (Everywhere is Bethlehem (Christmas album))
1993 Immer mittendrin (Always right in the middle)
1994 Liebe hin - Liebe her (Love to - Love fro)
1996 Verdammt ehrlich (Damn honest)
1998 Für alle Träumer (For all dreamers)
1999 Ungeschminkt (Unadorned)
2001 Hellwach (Wide awake)
2003 Mitten im Licht (In the middle of the light)
2004 Gute Nachricht (Good news)
2006 Wir sind nur Gast auf dieser Welt (Best Of) (We're just guests in this world)
2007 So long and goodbye (Live-Album)
2008 Die unvollendeten Lieder (The unfinished songs)

The debut album 'Komm, lass uns miteinander reden' was originally published as 'Applaus für Hanne Haller.' This discography only contains her studio albums and official 'Best of' compilations. Other compilations and re-releases exist from other companies.

References[edit]

^'Ramona Leiß: Lesben-Glück mit Hanne Haller' [Ramona Leiß: Lesbian happiness with Hanne Haller]. FOCUS Online (in German). 2008-11-05. Retrieved 2016-05-02.
^Weidemann, Carsten (2008-05-12). 'TV-Moderatorin Ramona Leiß outet sich' [TV Presenter Ramona Leiß Comes Out]. www.queer.de (in German). Retrieved 2016-05-02.

External links[edit]

http://www.hannehaller-fanpage.de/ Hanne Haller Fanpage
Hanne Haller discography at Discogs

Retrieved from 'https://en.wikipedia.org/w/index.php?title=Hanne_Haller&oldid=994358899'

igcw.netlify.com › Kurt Von Haller Roulette Lexikon ▲▲

Dec 19, 2018 Hello, I am new in this forum and would like to ask a question regarding European Roulette. (Single Zero Roulette) In the Roulette Lexikon from Kurt von Haller he writes, that the last open number should show up on average after 132 spins.

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I bet Kurt Von Haller made more money selling his book than he did playing roulette

If he made $1 selling books, then this statement is true. Come to think of it, even if he lost money on his book it is probably still true. Roulette challenges

Beware, I work for the dark side.. We have cookies

If the question is how long will it take for every number to appear in double-zero roulette, the answer is 160.6602765, on average. This is the sum of the inverse of every integer from 1 to 38.

It's not whether you win or lose; it's whether or not you had a good bet.

If the question is how long will it take for every number to appear in double-zero roulette, the answer is 160.6602765, on average. This is the sum of the inverse of every integer from 1 to 38.

the OP questions 37. Where it came from
that is just 1/p where p=1/37
handy tables
0 Roulette (155.4586903)

# of numbers	average # of spins	cumulative sum
1	1	1
2	1.027777778	2.027777778
3	1.057142857	3.084920635
4	1.088235294	4.173155929
5	1.121212121	5.29436805
6	1.15625	6.45061805
7	1.193548387	7.644166437
8	1.233333333	8.877499771
9	1.275862069	10.15336184
10	1.321428571	11.47479041
11	1.37037037	12.84516078
12	1.423076923	14.2682377
13	1.48	15.7482377
14	1.541666667	17.28990437
15	1.608695652	18.89860002
16	1.681818182	20.58041821
17	1.761904762	22.34232297
18	1.85	24.19232297
19	1.947368421	26.13969139
20	2.055555556	28.19524694
21	2.176470588	30.37171753
22	2.3125	32.68421753
23	2.466666667	35.1508842
24	2.642857143	37.79374134
25	2.846153846	40.63989519
26	3.083333333	43.72322852
27	3.363636364	47.08686488
28	3.7	50.78686488
29	4.111111111	54.897976
30	4.625	59.522976
31	5.285714286	64.80869028
32	6.166666667	70.97535695
33	7.4	78.37535695
34	9.25	87.62535695
35	12.33333333	99.95869028
36	18.5	118.4586903
37	37	155.4586903

The average is not the mode (The 'mode' is the value that occurs most often)
or median (The 'median' is the 'middle' value or close to 50%)
median = spin 147 @ 0.501522154
mode = 133 @ 0.0106293156
00 Roulette (160.6602765)

# of numbers	average # of spins	cumulative sum
1	1	1
2	1.027027027	2.027027027
3	1.055555556	3.082582583
4	1.085714286	4.168296868
5	1.117647059	5.285943927
6	1.151515152	6.437459079
7	1.1875	7.624959079
8	1.225806452	8.85076553
9	1.266666667	10.1174322
10	1.310344828	11.42777702
11	1.357142857	12.78491988
12	1.407407407	14.19232729
13	1.461538462	15.65386575
14	1.52	17.17386575
15	1.583333333	18.75719908
16	1.652173913	20.409373
17	1.727272727	22.13664572
18	1.80952381	23.94616953
19	1.9	25.84616953
20	2	27.84616953
21	2.111111111	29.95728064
22	2.235294118	32.19257476
23	2.375	34.56757476
24	2.533333333	37.1009081
25	2.714285714	39.81519381
26	2.923076923	42.73827073
27	3.166666667	45.9049374
28	3.454545455	49.35948285
29	3.8	53.15948285
30	4.222222222	57.38170508
31	4.75	62.13170508
32	5.428571429	67.56027651
33	6.333333333	73.89360984
34	7.6	81.49360984
35	9.5	90.99360984
36	12.66666667	103.6602765
37	19	122.6602765
38	38	160.6602765

median = spin 152 @ 0.501599171
mode = 138 @ 0.010333952
still interesting one brings up this question
Roulette Haller

Sally

I Heart Vi Hart

If the question is how long will it take for every number to appear in double-zero roulette, the answer is 160.6602765, on average. This is the sum of the inverse of every integer from 1 to 38.

The sum of the inverse of every integer from 1 to 38 is 4.2279020133. Using the inverse of every integer, it would take like 10^70 of them to get to 160. (160.66 is the harmonic series up to 38 times 38; using 37 for single zero roulette it is is 155)
(I learned this one when calculating the expected longest drought for a Super Bowl or World Series)

mustangsally

(160.66 is the harmonic series up to 38 times 38; using 37 for single zero roulette it is is 155)

being specific using pari/gp calculator found here
https://pari.math.u-bordeaux.fr/gp.html
a=sum(k=1,37,37/(37-(k-1)))
0 Roulette
00 Roulette
this is the short way to an answer
Sally

Wizard
Administrator

You're right. I forgot to say to multiply by 38.

It's not whether you win or lose; it's whether or not you had a good bet.

Thanks guys!

the OP questions 37. Where it came from
that is just 1/p where p=1/37
The average is not the mode (The 'mode' is the value that occurs most often)
or median (The 'median' is the 'middle' value or close to 50%)
median = spin 147 @ 0.501522154
mode = 133 @ 0.0106293156

Slot machines as skinner boxes. The primary difference was the video effects were then added to the gameplay. They often present mini-events after each win and during each engagement. are the most interactive online slots featuring latest 3D graphic developments.

I agree on the median. Here is my transition matrix.

0.027	0.973	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0.0541	0.9459	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0.0811	0.9189	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0.1081	0.8919	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0.1351	0.8649	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0.1622	0.8378	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0.1892	0.8108	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0.2162	0.7838	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0.2432	0.7568	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0.2703	0.7297	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0.2973	0.7027	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0.3243	0.6757	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0.3514	0.6486	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0.3784	0.6216	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.4054	0.5946	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.4324	0.5676	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.4595	0.5405	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.4865	0.5135	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.5135	0.4865	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.5405	0.4595	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.5676	0.4324	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.5946	0.4054	0	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.6216	0.3784	0	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.6486	0.3514	0	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.6757	0.3243	0	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.7027	0.2973	0	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.7297	0.2703	0	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.7568	0.2432	0	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.7838	0.2162	0	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.8108	0.1892	0	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.8378	0.1622	0	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.8649	0.1351	0	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.8919	0.1081	0	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.9189	0.0811	0	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.9459	0.0541	0
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0.973	0.027
0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	1

If the table is too big, cell (x,x) = x/37 and cell (x,x+1) = (37-x)/37), and every other cell is zero.

It's not whether you win or lose; it's whether or not you had a good bet.

I agree on the median. Here is my transition matrix.

to point out little differences in building a transition matrix (both are correct, one needs some special attention after calculations)
The Wizard's transition matrix (where rows sum to 1) starts with the 1st spin already completed.
I was taught to always start at 0 to make sure one does not forget to add 1 to calculations of the matrix.
(both methods are perfectly fine to use)
My TM is A, the Wizards is B (in the photo below - Wizard's values have been rounded down)
the column 1,2,3,4 is the row number and not the 'state name' for Matrix A but is correct for Matrix B
(Matrix A row names is just the row value - 1)
after raising the Wizards TM to the 146th power
(in the photo below)
we find the median (0.50141 - values have been rounded)
we must add 1 to 146 = 147 for the median (for the example 37 number Roulette)
distribution to only 160 spins
using R code section 3r.
https://sites.google.com/view/krapstuff/coupon-collecting
remember, we can only raise a square matrix to a power (as in B^146)
Enjoy

winsome johnny (not Win some johnny)

How about a math proof?

Assume there are N numbers, and K of them have already come up at least once.
This is equivalent to, 'If you have N balls, K of which are red and the other N-K are white, how many draws with replacement (i.e. when you draw a ball, you put it back) should it take before you draw a white ball?'
The probability of doing it in exactly D draws is (K / N)^D-1 x (N - K) / N
= (K^D-1 (N - K)) / N^D
The expected number is
1 x (N - K) / N
+ 2 x K (N - K) / N²
+ 3 x K² (N - K) / N³
+ 4 x K³ (N - K) / N⁴
+ ..
= (N - K) / N x (1 + 2 (K / N) + 3 (K / N)² + 4 (K / N)³ + ..)
= (N - K) / N x (1 + (K / N) + (K / N)² + (K / N)³ + ..)²
= (N - K) / N x (1 / (1 - (K / N))², since K < N
= (N - K) / N x (1 / ((N - K) / N))²
= (N - K) / N x (N / (N - K))²
= (N - K) / N x N² / (N - K)²
= N / (N - K)
At the start, K = 0; after each number is drawn for the first time, K increases by 1.
The total number is the number needed to get the first number + the number to get the
second different number once you have already drawn one + the number needed to get the
third different number once you have already drawn two different numbers + .. + the number
needed to get the Nth different number once you have already drawn N-1 different numbers
This is is N / N + N / (N-1) + N / (N-2) + .. + N / 2 + N
= N x (1 / N + 1 / (N-1) + .. + 1 / 3 + 1 / 2 + 1)

Hello,
I am new in this forum and would like to ask a question regarding European Roulette. (Single Zero Roulette)
In the Roulette Lexikon from Kurt von Haller he writes, that the last open number should show up on average after 132 spins.
Theoretically after 169 spins (132+37).
I could not find any more information on the internet about this topic. Can you confirm this numbers?
And why is it 37+132 = 169 spins? I don't understand this.
Regards

it can show up on the very next spin, right??

'Last open number' is rather ambiguous. There could be more than one sleeper for a long time and there no reason to believe that any number will become 'due' in any specific number of additional spins, merely by virtue of it achieving lone sleeper status. And frankly, if you're tracking sleepers, by the time you've eliminated other numbers to get to your one lone number, new numbers may have started sleeping, robbing that long sleeper of it's status.
At any rate..
The formula ( 36/37 ) ^ x shows the odds of a specific number NOT hitting in x spins.
When x = 132, the value is .026872 - the first time the value falls below .027027, which is the odds for any number hitting on any single spin.
Note that there is no reason to believe that a number 'should' hit at that point. I'm just guessing that the author chose to find significance there.
I have no idea what the +37 means.

Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁 Note that the same could be said for Religion. I.E. Religion is nothing more than organized superstition. 🤗

There are 37 numbered slots in single zero roulette
You add the individual integers in that number (3+7) = 10
Zero has no significance so you drop that from 10 which leaves 1
69 is the number of verbal sexuality and jts important to make verbal love with the wheel so you add that
The final result 1 added to 69 is 169
Hope that helps!

sure it can come up in the very next spin.
But the calculation from Kurt von Haller (he wrote a well known Roulette-Book) says that the average is 169.
I just would like to know if there are more sources which can confirm this Statement.

Quote: masterj

I could not find any more information on the internet about this topic. Can you confirm this numbers?
And why is it 37+132 = 169 spins? I don't understand this.

169 is then not right.
118.4586903 is the average number of spins to get 36 of the 37 numbers
add 37 to that 155.4586903
that is what I get calculating getting all 37 numbers starting at 0

Roulette Challenges

> N.mean(37)
[1] 155.4587
'last open number' could have different meanings to different people
Sally

never heard of the guy. Is this a conditional probability problem? given the 37 numbers, how long on average does it take to get 36 of them?
then add 37 to that for the last number?
If that is what the secret is
169 is then not right.
118.4586903 is the average number of spins to get 36 of the 37 numbers
add 37 to that 155.4586903
that is what I get calculating getting all 37 numbers starting at 0
> an(37)
[1] 155.4587
'last open number' could have different meanings to different people
Sally

Thanks for this post from:

Roulette Half Wheel Strategy

for me 'last open number' means if for example after 120 spins we got 36 out of 37 numbers, then on average how many spins we have to wait for the last one to show up?
I know we can get this last number in the next spin, and it can't show up for the next x spins.
The number of spins it would take on average to get that number from that point on, is exactly the same as if it wasn’t the last number standing.

EvenBob

) says that the average is 169.

So what. Even if true, how would this
benefit you in any way. The number
could sleep for 400 spins and show

Kurt Von Haller Roulette Lexikon Online

up 3 times in a row.

'It's not enough to succeed, your friends must fail.' Gore Vidal

michael99000

Kurt Von Haller Roulette Lexikon 2016

I bet Kurt Von Haller made more money selling his book than he did playing roulette

Kurt Von Haller Roulette Lexikon Free

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